√ (1-x^2)y''-2xy' 2y=0 y1=x 268313
06 radians 10 radians 369 degrees 531 degrees0 votes 1 answer It is said that if given solution #y_1#, the second one is given as #y_2=v(x)y_1# Where in this problem, #y_1=1/x# If #y_2=v(x)1/x# , then the derivatives are Solved Solve 1 X 2 Y 2xy 2y 0 Via Simple Chegg Com (1-x^2)y''-2xy' 2y=0 y1=x